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Applied assessment — Advanced Statistics Laboratory Select correct statistical tests, interpret spreadsheet output, and calculate control limits and capability indices for garment process data.
Every question asks you to decide, judge or calculate from a situation rather than recall a definition. 5 questions, 75 per cent to pass, as many attempts as you like, and your best score is kept on this device. Free, and a self-study assessment rather than an accredited examination.
4 of 5 needed to pass
1. A quality engineer wants to compare mean seam-strength results from two different thread suppliers using 30 samples from each, with roughly normal distributions and unequal variances. Which test is most appropriate? Choose one answer.
One-sample t-test Simple linear regression Chi-square test of independence Two-sample t-test assuming unequal variances (Welch's t-test)
2. A subgroup of 5 collar measurements has values 15.2, 15.4, 15.1, 15.3, 15.5 cm. If the historical average range across subgroups is 0.35 cm and the d2 constant for n=5 is 2.326, what does an Xbar chart use as the estimate of process standard deviation? Choose one answer.
2.326 / 0.35 = about 6.65 cm 0.35 / 2.326 = about 0.150 cm 0.35 x 2.326 = about 0.814 cm The standard deviation of the five listed values directly
3. A scatter plot of fabric GSM against dye-bath temperature shows a moderate upward trend with visible scatter, and a spreadsheet regression reports R-squared of 0.42. What is the most defensible interpretation? Choose one answer.
Temperature causes 100 percent of GSM variation Temperature explains about 42 percent of the variation in GSM; other factors and noise account for the rest There is no relationship because R-squared is below 0.5 The relationship must be non-linear because R-squared is not 1.0
4. A process has a specification width of 0.6 cm and a process spread (6 sigma) of 0.5 cm, with the process mean centered on the target. Which capability conclusion follows? Choose one answer.
Cp is about 0.83, indicating the process is not capable Cp cannot be calculated without the sample size Cp equals the specification width alone, 0.6 Cp is about 1.2, indicating the process spread fits comfortably within specification
5. Three operators each measure the same 10 garments twice using a tape measure, and a Gage R&R study reports total Gage R&R at 35 percent of total variation. What should the team conclude? Choose one answer.
The process itself is out of control The sample size of 10 garments was too large The measurement system is acceptable with no action needed The measurement system needs improvement before trusting the process data it produces
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